Question Detail

PHY 101 PHY 101 Past Questions Objective Question
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Question

Three particles of masses m₁ = 6.0 kg, m₂ = 4.0 kg and m₃ = 4.0 kg and distance a = 2.0 cm. What is the net gravitational force F_net on particle m₁ due to the other particles?
Options
A 3.00 × 10⁻⁶ N
B 10⁻⁶ N
C 4.41 × 10⁻⁷ N
Correct Answer
D 4.10 × 10⁻⁶ N
Correct Answer

Option C is the correct answer.

Detailed Explanation

Assuming particles are arranged with m₁ at one corner of a square of side a = 0.02 m, with m₂ and m₃ at adjacent corners. Force from m₂: F₂ = G(6)(4)/(0.02)². Force from m₃: F₃ = G(6)(4)/(0.02)². These forces are perpendicular. F_net = √(F₂² + F₃²) = √2 × G × 24/(0.0004) = √2 × 6.67×10⁻¹¹ × 24/0.0004 = 4.41 × 10⁻⁷ N.

Hint

Calculate each force using F = Gm₁m₂/r², then add as vectors.

Question Info

Course: PHY 101
Topic: PHY 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 840 of 1250
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