Question Detail

PHY 101 PHY 101 Past Questions Objective Question
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Question

A ball is thrown upward at a velocity of 30 m/s at an angle of 36.9° above the horizontal. What are the components of its velocity?
Options
A 30 m/s at 36.9° east of south
B 24 m/s east, 18 m/s north
Correct Answer
C 30 m/s at 36.9° east of south
D 70 m/s at 36.9° east of south
Correct Answer

Option B is the correct answer.

Detailed Explanation

The components are found using trigonometry: v_x = v cosθ = 30 cos(36.9°) ≈ 30 × 0.8 = 24 m/s (east), v_y = v sinθ = 30 sin(36.9°) ≈ 30 × 0.6 = 18 m/s (north). This matches option B.

Hint

Use v_x = v cosθ and v_y = v sinθ for the horizontal and vertical components.

Question Info

Course: PHY 101
Topic: PHY 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 869 of 1250
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