Question Detail
Question
A 2.8 g bullet traveling at a speed of 540 m/s enters a wall and exits the other side with a speed of 120 m/s. Compute the amount of energy transferred?
Correct Answer
Option C is the correct answer.
Detailed Explanation
The energy transferred is the loss in kinetic energy: ΔKE = ½m(v_i² - v_f²). Mass = 2.8 g = 0.0028 kg. v_i² = (540)² = 291,600, v_f² = (120)² = 14,400. v_i² - v_f² = 277,200. ΔKE = 0.5 × 0.0028 × 277,200 = 0.0014 × 277,200 = 388.08 J ≈ 388 J.
Hint
Energy transferred = change in kinetic energy = ½m(v_i² - v_f²).