Question Detail

PHY 101 PHY 101 Past Questions Objective Question
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Question

The angular momentum of a flywheel having a rotational inertia of 0.140 kg·m² about its central axis decreases from 3.00 to 0.80 kg·m²/s in 1.5 s. What is the average torque acting on the flywheel about the central axis during this period?
Options
A 13.00 Nm
B 9.20 Nm
C 1.47 Nm
Correct Answer
D 15.70 Nm
Correct Answer

Option C is the correct answer.

Detailed Explanation

Torque = rate of change of angular momentum = (L_f - L_i)/t = (0.80 - 3.00)/1.5 = (-2.20)/1.5 = -1.467 Nm. Magnitude = 1.47 Nm.

Hint

τ = ΔL/Δt.

Question Info

Course: PHY 101
Topic: PHY 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 905 of 1250
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