Question Detail
Question
Find the tension in the rope 1.2 m long for which a 1.5 kg particle resting on a table is attached to a fixed point on the table, if the particle is making 300 rev/min?
Correct Answer
Option B is the correct answer.
Detailed Explanation
Angular velocity ω = 300 rev/min = 300 × 2π/60 = 300 × 0.10472 = 31.416 rad/s. Centripetal force F = mω²r = 1.5 × (31.416)² × 1.2 = 1.5 × 987 × 1.2 = 1.5 × 1184.4 = 1776.6 N ≈ 1800 N.
Hint
Tension provides centripetal force: F = mω²r.