Question Detail
Question
If a body of mass 3 kg is dropped downwards, after 1 sec another ball is dropped downwards from the same point. What is the distance between them after 3 sec?
Correct Answer
Option A is the correct answer.
Detailed Explanation
First ball falls for 3 s: s₁ = ½gt² = ½×9.8×9 = 44.1 m. Second ball falls for 2 s (dropped 1 s later): s₂ = ½×9.8×4 = 19.6 m. Distance between them = 44.1 - 19.6 = 24.5 m ≈ 25 m.
Hint
Distance = difference in distances fallen.