Question Detail
Question
At time t = 0 a car has a velocity of 16 m/s. It slows down with an acceleration given by -0.50t, in m/s² for t in seconds. It stops at t = ?
Correct Answer
Option D is the correct answer.
Detailed Explanation
a = dv/dt = -0.5t. Integrate: v = ∫ -0.5t dt = -0.25t² + C. At t=0, v=16, so C=16. v = 16 - 0.25t². Set v=0: 0 = 16 - 0.25t² → 0.25t² = 16 → t² = 64 → t = 8 s.
Hint
Integrate acceleration to get velocity.