Question Detail
Question
An object moving along a circular path of radius 2.5 m has a period of 0.25 s. Calculate its centripetal acceleration to the nearest whole number.
Correct Answer
Option C is the correct answer.
Detailed Explanation
Angular velocity ω = 2π/T = 2π/0.25 = 8π = 25.13 rad/s. Centripetal acceleration a = ω²r = (25.13)² × 2.5 = 631.5 × 2.5 = 1578.75 m/s² ≈ 1580 m/s².
Hint
a_c = ω²r, ω = 2π/T.