Question Detail
Question
A Fire-fighter who weighs 712 N slides down a vertical pole with an acceleration of 3.00 m/s², directed downward. What is the magnitude of the force on the Fire-fighter from the pole?
Correct Answer
Option A is the correct answer.
Detailed Explanation
Weight mg = 712 N, so m = 712/9.8 = 72.65 kg. Net force downward = mg - f = ma → f = m(g - a) = 72.65 × (9.8 - 3) = 72.65 × 6.8 = 494 N.
Hint
f = m(g - a) when sliding down with acceleration a.