Question Detail
Question
A missile is launched with a speed of 50 m/s at an angle 40° above the surface of a warship. Ignoring the effects of air resistance, determine the maximum height achieved by the missile.
Correct Answer
Option A is the correct answer.
Detailed Explanation
Maximum height H = (u² sin²θ)/(2g) = (50² × sin²40°)/(2×9.8) = (2500 × 0.4132)/19.6 = 1033/19.6 = 52.7 m ≈ 51.6 m if g=10? With g=10: (2500×0.4132)/20 = 1033/20=51.65 m.
Hint
H = (u² sin²θ)/(2g).