Question Detail
Question
A ball was thrown from the ground, and its velocity was 10 m/s at an altitude of 15 m above the ground. Calculate the velocity at the point of throw, and the maximum height reached.
Correct Answer
Option B is the correct answer.
Detailed Explanation
Using v² = u² - 2gh, at altitude 15 m, v = 10 m/s. So 10² = u² - 2×9.8×15 → 100 = u² - 294 → u² = 394 → u = 19.85 m/s ≈ 20 m/s. Maximum height H = u²/(2g) = 400/19.6 = 20.4 m ≈ 20 m.
Hint
Use v² = u² - 2gh and H = u²/(2g).