Question Detail
Question
A man walks 1 km due east and then √3 km due north. Find his displacement.
Correct Answer
Option B is the correct answer.
Detailed Explanation
Displacement magnitude = √(1² + (√3)²) = √(1 + 3) = √4 = 2 km. Direction θ = tan⁻¹(√3/1) = tan⁻¹(1.732) = 60° north of east. So 2 km N 60° E.
Hint
Use Pythagorean theorem and trigonometry.