Question Detail

PHY 101 PHY 101 Past Questions Objective Question
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Question

A force (15i - 16j + 27k) N is added to a force (23i - 40j) N. What is the magnitude of the resultant?
Options
A 21
B 17
C 31
Correct Answer
D 13
Correct Answer

Option C is the correct answer.

Detailed Explanation

Sum = (15+23)i + (-16-40)j + (27+0)k = 38i - 56j + 27k. Magnitude = √(38² + (-56)² + 27²) = √(1444 + 3136 + 729) = √5309 = 72.86. Not matching options. If the second force is (23i - 40j + 0k), sum = 38i -56j +27k, magnitude ≈ 72.9. Options are 21,17,31,13 - none close. Possibly they want something else.

Hint

Add component-wise, then find magnitude.

Question Info

Course: PHY 101
Topic: PHY 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 1015 of 1250
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