Question Detail

PHY 101 PHY 101 Past Questions Objective Question
Take CBT

Question

When a stone is thrown directly upwards with initial velocity of 30.0 m/s, what will be the maximum height it will reach and when will it be? Acceleration due to gravity is 10 m/s².
Options
A 45 m in 3 s
Correct Answer
B 90 m in 6 s
C 1.5 m in 3 s
D 90 m in 3 s
Correct Answer

Option A is the correct answer.

Detailed Explanation

Time to reach max height t = u/g = 30/10 = 3 s. Max height H = u²/(2g) = 900/20 = 45 m.

Hint

t = u/g, H = u²/(2g).

Question Info

Course: PHY 101
Topic: PHY 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 1053 of 1250
Previous Course Details Next