Question Detail

PHY 101 PHY 101 Past Questions Objective Question

Question

Taking density (ρ), velocity (v), and area (a) to be the fundamental units, then the dimensions of force is:
Options
A [a v² ρ]
Correct Answer
B [a v ρ]
C [a v ρ²]
D [a v ρ]
Correct Answer

Option A is the correct answer.

Detailed Explanation

Force has dimensions [M L T⁻²]. Density ρ has dimensions [M L⁻³]. Velocity v has dimensions [L T⁻¹]. Area a has dimensions [L²]. We need to combine a, v, and ρ to get [M L T⁻²]. Let F ∝ a^x v^y ρ^z. Then [L²]^x [L T⁻¹]^y [M L⁻³]^z = M^z L^(2x + y - 3z) T^(-y). Equating: M: z = 1. T: -y = -2 => y = 2. L: 2x + y - 3z = 2x + 2 - 3 = 2x -1 = 1 => 2x = 2 => x = 1. So F ∝ a¹ v² ρ¹. Thus dimensions are [a v² ρ].

Hint

Express the dimensions of force in terms of mass, length, and time, then substitute the dimensions of the given quantities and solve for the exponents.

Question Info