Question Detail
Question
A projectile is fired from the surface of the Earth with a speed of 200 m/s at an angle of 30° above the horizontal. If the ground is level, what is the maximum height reached by the projectile?
Correct Answer
Option C is the correct answer.
Detailed Explanation
Maximum height H = (u² sin²θ) / (2g). Here u = 200 m/s, θ = 30°, sin30° = 0.5, so sin²θ = 0.25. Using g = 10 m/s², H = (200² × 0.25) / (2×10) = (40000 × 0.25) / 20 = (10000) / 20 = 500 m.
Hint
Use the formula for maximum height of a projectile: H = (u² sin²θ)/(2g).