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PHY 101 PHY 101 Past Questions Objective Question
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Question

The acceleration of a car is given as a function of time as a(t) = (2.0 - 0.2t) m/s². If the position and velocity at time t=0 is x = 0 and v = 10 m/s respectively, what is the velocity of the car after t = 2.0 s?
Options
A 1.8 m/s
B 13.6 m/s
Correct Answer
C 40 m/s
D 80 m/s
Correct Answer

Option B is the correct answer.

Detailed Explanation

Velocity v(t) = ∫ a(t) dt = ∫ (2.0 - 0.2t) dt = 2.0t - 0.1t² + C. At t=0, v=10, so C=10. Then v(2) = 2.0×2 - 0.1×4 + 10 = 4 - 0.4 + 10 = 13.6 m/s.

Hint

Integrate acceleration to get velocity, using initial condition.

Question Info

Course: PHY 101
Topic: PHY 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 1107 of 1250
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