Question Detail

PHY 101 PHY 101 Past Questions Objective Question

Question

A car is travelling eastward at a speed of 40 m/s. But a 30 m/s wind is blowing southward. What is the direction and speed of the car relative to its original direction?
Options
A 50 m/s at 36.9° east of south
Correct Answer
B 40 m/s at 36.9° east of south
C 30 m/s at 36.9° east of south
D 70 m/s at 36.9° east of south
Correct Answer

Option A is the correct answer.

Detailed Explanation

The car's velocity relative to ground is 40 m/s east. Wind is blowing southward at 30 m/s, so the velocity of car relative to air is vector sum? Actually, the question might be ambiguous. If the car is moving east and wind is south, the resultant velocity relative to ground is √(40² + 30²) = 50 m/s. Direction: tan θ = 30/40 = 0.75, θ = 36.9° south of east, or equivalently 53.1° east of south. But option A says 50 m/s at 36.9° east of south, which is the same as 53.1° south of east. So A is correct.

Hint

Use vector addition: the two velocities are perpendicular.

Question Info