Question Detail

PHY 101 PHY 101 Past Questions Objective Question
Take CBT

Question

A 4 kg ball and a 2 kg ball have their centers separated by a distance of 40 cm. What is the force of attraction between them? (gravitational constant G = 6.673×10⁻¹¹ N m²/kg²)
Options
A 1.3 × 10⁻⁹ N
B 3.3 × 10⁻⁹ N
Correct Answer
C 6.5 × 10⁻¹¹ N
D 3.1 × 10⁻¹¹ N
Correct Answer

Option B is the correct answer.

Detailed Explanation

F = G m₁ m₂ / r² = (6.673×10⁻¹¹ × 4 × 2) / (0.4)² = (6.673×10⁻¹¹ × 8) / 0.16 = (5.3384×10⁻¹⁰) / 0.16 = 3.3365×10⁻⁹ N ≈ 3.3 × 10⁻⁹ N.

Hint

Use Newton's law of universal gravitation.

Question Info

Course: PHY 101
Topic: PHY 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 1151 of 1250
Previous Course Details Next