Question Detail
Question
A particle moves along X-axis in such a way that its coordinate X varies with the time t according to the expression x = (8 - 5t + 8t²) meter. The initial velocity of the particle is:
Correct Answer
Option A is the correct answer.
Detailed Explanation
Velocity v = dx/dt = -5 + 16t. At t=0 (initial), v₀ = -5 m/s.
Hint
Differentiate the position function with respect to time to find velocity, then evaluate at t=0.