Question Detail

First, determine the mRNA sequence from the given DNA strand. The DNA is 5'-CGATATGCTGGC-3'. Assuming this is the template strand, the mRNA would be complementary and antiparallel. The mRNA would be 3'-GCUAUACGACCG-5', which is usually written 5'-GCCAGCAUAUCG-3'? Let's do it carefully: DNA template: 3' - C G T A T G C T G G C - 5' (if we flip the given strand). It's easier to find the coding strand. But we just need the number of amino acids. The DNA sequence has 12 bases (12/3 = 4 potential codons). Assuming no stop codon, it would code for 4 amino acids. Let's transcribe the given strand directly: DNA 5' C G A T A T G C T G G C 3'. The mRNA made from this template would be complementary: 3' G C U A U A C G A C C G 5'. Reading this mRNA 5'->3': 5' G C C A G U A U A G C 3'? This is messy. Simpler: The number of nucleotides in the coding sequence is 12. Each amino acid is coded by 3 nucleotides (a codon). 12 / 3 = 4 amino acids.