Question Detail
Question
How many of 160 F2 offspring from a monohybrid cross of a true breeding tall and short Pisum sativum will be heterozygote tall? A. 120 B. 40 C. 80 D. 60
Correct Answer
Option C is the correct answer.
Detailed Explanation
A monohybrid cross (TT x tt) gives F1 all Tt (tall). F2 from Tt x Tt gives genotypic ratio 1 TT : 2 Tt : 1 tt. So, out of 160 offspring, the number of heterozygotes (Tt) is (2/4) * 160 = 80. These are tall.
Hint
Heterozygotes are 2 out of every 4 offspring.