Question Detail
Question
Calculate the escape velocity from the surface of a star whose mass is 7.34 × 10²² kg and radius is 1.738 × 10⁶ m.
Correct Answer
Option A is the correct answer.
Detailed Explanation
Escape velocity v = √(2GM/R). G = 6.67 × 10⁻¹¹ Nm²/kg². v = √(2 × 6.67×10⁻¹¹ × 7.34×10²² / 1.738×10⁶) = √(2 × 6.67×7.34×10¹¹ / 1.738×10⁶) = √(97.96×10⁵ / 1.738) = √(5.64×10⁶) ≈ 2374 m/s.
Hint
Use escape velocity formula v = √(2GM/R).