Question Detail
Question
A 4kg object attached to a rope makes 200 rev/min. If the tension in the rope is 20000N, find the length of the rope
Correct Answer
Option B is the correct answer.
Detailed Explanation
The tension provides the centripetal force: T = mω²r. ω = 200 rpm = 200 × (2π/60) = (400π/60) = (20π/3) ≈ 20.94 rad/s. So, r = T/(mω²) = 20000 / (4 × (20.94)²) = 20000 / (4 × 438.5) = 20000 / 1754 ≈ 11.4 m. This doesn't match options. If we use the provided numbers differently: If T=20000N, m=4kg, f=200/60=3.333 Hz, ω=2πf=20.94 rad/s, r=20000/(420.94²)=20000/(4438.5)=20000/1754=11.4m. None match. Possibly radius is small, so maybe T is 2000N? If T=2000N, r=2000/1754=1.14m, close to 1.27m if ω is slightly different. Using exact: ω=200*2π/60=20.943, ω²=438.65, mω²=1754.6, r=2000/1754.6=1.14. If T=20000, r=11.4. Given options, maybe they used T=2000N? Option B 1.27 is closest if we use g or something else. Possibly a misprint.
Hint
Centripetal force F_c = mω²r. Convert rpm to rad/s.