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Without the diagram, we assume typical setup: ropes at ends, weight at center. Total weight = 60×9.8 = 588 N. If symmetric, each rope tension = 294 N. Since 353N is an option, maybe one rope is at an angle or not at the end. If T₂ is the tension in one rope and the beam is horizontal, taking moments about the point where the other rope attaches gives T₂ × (distance from pivot) = mg × (distance to center). If pivot is at one end and T₂ at the other, T₂ × 8 = 588 × 4 => T₂ = 294 N. Not 353. If pivot is at some other point, or if there's an angle, we'd need more info. Possibly the answer is 353N if the rope is at an angle of 45° or something.