Question Detail
Question
Find the sixth root of 64.
Correct Answer
Option D is the correct answer.
Detailed Explanation
64 = 2^6, so the sixth roots of 64 are given by 2 × e^(2πik/6) = 2e^(iπk/3) for k=0,1,2,3,4,5. These are the six complex numbers with magnitude 2 and arguments that are multiples of π/3.
Hint
Express 64 as 2^6 and use De Moivre's theorem for roots.