Question Detail
Question
Expressing sin⁻¹x in terms of z, we have:
Correct Answer
Option B is the correct answer.
Detailed Explanation
sin⁻¹x = -i ln(ix + √(1-x²)) or in some contexts expressed using logarithms. The correct form involves √(1-x²). For z = ix, the expression becomes something like ln(z ± √(1-z²)).
Hint
Recall the logarithmic form of inverse trigonometric functions.