Question Detail

MTH 101 MTH 101 Past Questions Objective Question
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Question

Find the parametric equation of the circle x² + y² - 2x - 6y - 6 = 0.
Options
A x = 2 + 4cosθ, y = 4 + 4sinθ
B x = 1 + 4cosθ, y = 3 + 4sinθ
Correct Answer
C x = 3 + 4cosθ, y = 1 + 4sinθ
D x = 4 + 4cosθ, y = 1 + 4sinθ
Correct Answer

Option B is the correct answer.

Detailed Explanation

Complete the square: x² - 2x + y² - 6y = 6 → (x² - 2x + 1) + (y² - 6y + 9) = 6 + 1 + 9 = 16 → (x - 1)² + (y - 3)² = 16 = 4². So center (1,3), radius 4. Parametric equations: x = 1 + 4cosθ, y = 3 + 4sinθ.

Hint

Complete the square to find center and radius, then write parametric form.

Question Info

Course: MTH 101
Topic: MTH 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 409 of 696
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