Question Detail

MTH 101 MTH 101 Past Questions Objective Question
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Question

Find the equation of a circle with center (-3,2) and radius 4.
Options
A x² + y² + 4y - 6x + 3 = 0
B x² + y² - 4y - 6x + 3 = 0
C x² + y² + 6x - 4y - 3 = 0
Correct Answer
D x² + y² + 6x + 4y - 3 = 0
Correct Answer

Option C is the correct answer.

Detailed Explanation

Center (-3,2), radius 4. Equation: (x+3)² + (y-2)² = 16 → x² + 6x + 9 + y² - 4y + 4 = 16 → x² + y² + 6x - 4y + 13 - 16 = 0 → x² + y² + 6x - 4y - 3 = 0.

Hint

Use the standard form (x-h)² + (y-k)² = r².

Question Info

Course: MTH 101
Topic: MTH 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 450 of 696
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