Question Detail

MTH 101 MTH 101 Past Questions Objective Question

Question

sin²x + sin²x cot²x = ?
Options
A cot²x + 1
B 1
Correct Answer
C sin²x + 1
D cot 2x - 1
Correct Answer

Option B is the correct answer.

Detailed Explanation

sin²x + sin²x cot²x = sin²x(1 + cot²x) = sin²x · csc²x = sin²x · (1/sin²x) = 1.

Hint

Factor out sin²x and use the identity 1 + cot²θ = csc²θ.

Question Info