Question Detail
Question
What is the mass percent composition of bromine in haloethane (C₂HBrClF₃)?
Correct Answer
Option B is the correct answer.
Detailed Explanation
Molar mass = (2×12.01) + (1×1.008) + (1×79.90) + (1×35.45) + (3×19.00) = 24.02 + 1.008 + 79.90 + 35.45 + 57.00 = 197.378 g/mol. Mass of Br = 79.90 g/mol. (79.90 / 197.378) × 100% = 40.48% ≈ 40.51%.
Hint
Calculate the total molar mass first, then the mass contribution of bromine.