Question Detail

CHM 101 CHM 101 Past Questions Objective Question
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Question

Calculate the solubility product of 0.001 mol dm⁻³ solution of Ag₂S at 25 °C
Options
A 4.0 × 10⁻⁹ mol³ dm⁻⁹
Correct Answer
B 2.0 × 10⁻⁹ mol³ dm⁻⁹
C 1.0 × 10⁻⁹ mol³ dm⁻⁹
D 2.0 × 10⁻⁶ mol³ dm⁻⁹
Correct Answer

Option A is the correct answer.

Detailed Explanation

Ag₂S(s) ⇌ 2Ag⁺(aq) + S²⁻(aq). If solubility s = 0.001 M, then [Ag⁺] = 2s = 0.002 M, [S²⁻] = s = 0.001 M. Ksp = [Ag⁺]²[S²⁻] = (0.002)²(0.001) = (4×10⁻⁶)(1×10⁻³) = 4.0 × 10⁻⁹ mol³ dm⁻⁹.

Hint

Write the dissociation equation and relate ion concentrations to molar solubility.

Question Info

Course: CHM 101
Topic: CHM 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 1036 of 1872
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