Question Detail
Question
What is the work done in joules by a system of gas that expands at a constant pressure of 3 atm from a volume of 5 L to 26 L?
Correct Answer
Option B is the correct answer.
Detailed Explanation
Work done by the system: w = -PΔV. ΔV = 26 - 5 = 21 L. P = 3 atm. w = -3 atm × 21 L = -63 L·atm. Convert to joules: -63 L·atm × 101.325 J/L·atm = -6383.475 J ≈ -6383.4 J.
Hint
Use w = -PΔV (for constant pressure). Convert L·atm to J using 1 L·atm = 101.325 J.