Question Detail

CHM 101 CHM 101 Past Questions Objective Question

Question

Calculate the number of oxygen atoms in 0.520 mol of CaCO₃
Options
A 3.343 × 10²³
Correct Answer
B 33.43 × 10²³
C 3.343 × 10²⁴
D 33.43 × 10²⁴
Correct Answer

Option A is the correct answer.

Detailed Explanation

1 mol CaCO₃ contains 3 mol O atoms. 0.520 mol CaCO₃ contains 0.520 × 3 = 1.56 mol O atoms. Number of O atoms = 1.56 × 6.022 × 10²³ = 9.394 × 10²³. None of the options match this. Possibly the question meant 0.520 mol of oxygen atoms? If so, 0.520 × 6.022×10²³ = 3.13×10²³ ≈ 3.343×10²³? This seems inconsistent.

Hint

Multiply moles of compound by the number of O atoms per formula unit, then by Avogadro's number.

Question Info