Question Detail
Question
The percentage composition of chromium in BaCrO₄ is? [Ba = 137, Cr = 52, O = 16]
Correct Answer
Option C is the correct answer.
Detailed Explanation
Molar mass BaCrO₄ = 137 + 52 + (4×16) = 137 + 52 + 64 = 253 g/mol. %Cr = (52/253) × 100% = 20.55% ≈ 20.5%.
Hint
(Mass of Cr / molar mass of compound) × 100%.