Question Detail
Question
The weight of a millimole of (NH₄)₂HPO₄ is: [N=14; H=1; P=31; O=16]
Correct Answer
Option D is the correct answer.
Detailed Explanation
Molar mass = (2×14) + (9×1) + 31 + (4×16) = 28 + 9 + 31 + 64 = 132 g/mol. 1 millimole = 0.001 mol. Mass = 0.001 × 132 = 0.132 g.
Hint
Millimole = 1/1000 mole.