Question Detail
Question
What volume of water must be added to 200 mL of 0.75 M HCl to dilute the solution to 0.25 M?
Correct Answer
Option A is the correct answer.
Detailed Explanation
M₁V₁ = M₂V₂. (0.75)(200) = (0.25)(V₂). V₂ = 600 mL final volume. Water added = 600 - 200 = 400 mL.
Hint
Dilution formula: M₁V₁ = M₂V₂.