Question Detail

CHM 101 CHM 101 Past Questions Objective Question
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Question

Calculate the number of moles contained in 2.25 g of Mg(NO₃)₂ [Mg=24; N=14; O=16]
Options
A 0.0152
Correct Answer
B 148.3
C 0.0261
D 65.8
Correct Answer

Option A is the correct answer.

Detailed Explanation

Molar mass Mg(NO₃)₂ = 24 + 2×(14+48) = 24 + 124 = 148 g/mol. Moles = 2.25/148 = 0.0152 mol.

Hint

Moles = mass / molar mass.

Question Info

Course: CHM 101
Topic: CHM 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 1105 of 1872
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