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CHM 101 CHM 101 Past Questions Objective Question

Question

A 25.5 mL aliquot of HCl(aq) of unknown concentration was titrated with 51.2 mL of 0.113 M NaOH(aq) to the end point. What is the concentration of the HCl solution?
Options
A 1.02
B 0.114
C 0.454
D 0.227
Correct Answer
Correct Answer

Option D is the correct answer.

Detailed Explanation

HCl + NaOH → NaCl + H₂O (1:1 ratio). Moles NaOH = 0.0512 L × 0.113 M = 0.0057856 mol. Moles HCl = same. Concentration HCl = 0.0057856 mol / 0.0255 L = 0.2269 M ≈ 0.227 M.

Hint

Use M₁V₁ = M₂V₂ for monoprotic acid-base titrations.

Question Info