Question Detail
Question
If the equilibrium constant for the reaction: A + 2B ⇌ C + 5/2 D has a value of 4.0, what is the value of the equilibrium constant for the reaction 2C + 5D ⇌ 2A + 4B at the same temperature?
Correct Answer
Option D is the correct answer.
Detailed Explanation
For reaction 1: K₁ = [C][D]^(5/2) / [A][B]² = 4.0. The target reaction is the reverse of twice reaction 1. For reverse: K_rev = 1/K₁. For multiplying by 2: K = (1/K₁)² = (1/4)² = 1/16 = 0.0625 ≈ 0.063.
Hint
Reversing a reaction inverts K; multiplying coefficients by n raises K to the power n.