Question Detail
Question
The reaction A + 2B → product has the rate law, rate = k[A]²[B]. If the concentration of B is doubled while that of A is unchanged, by what factor will the rate of reaction increase?
Correct Answer
Option A is the correct answer.
Detailed Explanation
Initial rate = k[A]²[B]. If [B] doubles, new rate = k[A]²[2B] = 2 × k[A]²[B]. Factor = 2.
Hint
The rate depends on [B] to the first power, so doubling B doubles the rate.