Question Detail
Question
If 150.0 mL of a 0.100 M solution of silver nitrate is added to 200.0 mL of a 0.050 M solution of sodium chloride, what is the mass of solid silver chloride formed? [Ag = 108, Cl = 35.5, Na = 23, N = 14, O = 16]
Correct Answer
Option A is the correct answer.
Detailed Explanation
Balanced equation: AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq). Moles AgNO₃ = (0.150 L)(0.100 mol/L) = 0.0150 mol. Moles NaCl = (0.200 L)(0.050 mol/L) = 0.0100 mol. NaCl is the limiting reactant. Moles AgCl = 0.0100 mol. Mass AgCl = 0.0100 × (108 + 35.5) = 0.0100 × 143.5 = 1.435 g ≈ 1.44 g.
Hint
Determine the limiting reactant first by calculating moles of each.