Question Detail

CHM 101 CHM 101 Past Questions Objective Question
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Question

A 25.0 mL sample of hydrochloric acid requires 18.50 mL of 0.150 M sodium hydroxide for complete neutralization. What is the molarity of the hydrochloric acid?
Options
A 0.111 M
Correct Answer
B 0.222 M
C 0.333 M
D 0.444 M
Correct Answer

Option A is the correct answer.

Detailed Explanation

Balanced equation: HCl + NaOH → NaCl + H₂O. Moles NaOH = (0.01850 L)(0.150 mol/L) = 0.002775 mol. Moles HCl = 0.002775 mol. Molarity HCl = 0.002775 mol / 0.0250 L = 0.111 M.

Hint

The mole ratio is 1:1 for HCl and NaOH.

Question Info

Course: CHM 101
Topic: CHM 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 1223 of 1872
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