Question Detail

CHM 101 CHM 101 Past Questions Objective Question
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Question

For the reaction A + B → C, the following data was obtained: Expt 1: [A]=0.1, [B]=0.1, rate=0.02; Expt 2: [A]=0.2, [B]=0.1, rate=0.04; Expt 3: [A]=0.1, [B]=0.2, rate=0.08. What is the rate law?
Options
A rate = k[A][B]
B rate = k[A]²[B]
C rate = k[A][B]²
Correct Answer
D rate = k[A]
Correct Answer

Option C is the correct answer.

Detailed Explanation

Comparing Expt 1 and 2: [B] constant, [A] doubles, rate doubles → first order in A. Comparing Expt 1 and 3: [A] constant, [B] doubles, rate quadruples → second order in B. Rate = k[A][B]².

Hint

Analyze how the rate changes when each reactant concentration is changed individually.

Question Info

Course: CHM 101
Topic: CHM 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 1244 of 1872
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