Question Detail
Question
The rate constant for a reaction is 2.0 × 10⁻³ s⁻¹ at 25°C and has an activation energy of 40 kJ/mol. What is the rate constant at 35°C? (R = 8.314 J/mol·K)
Correct Answer
Option B is the correct answer.
Detailed Explanation
T₁ = 298 K, T₂ = 308 K. ln(k₂/k₁) = (40000/8.314)(1/298 - 1/308) = (4811)(0.000109) = 0.524. k₂/k₁ = e⁰·⁵²⁴ = 1.69. k₂ = 1.69 × 2.0×10⁻³ = 3.38×10⁻³ ≈ 3.5×10⁻³ s⁻¹.
Hint
Use the Arrhenius equation in its two-point form.