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CHM 101 CHM 101 Past Questions Objective Question
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Question

For the reaction H₂(g) + Br₂(g) ⇌ 2HBr(g), Kp is 1.2 × 10⁵ at a certain temperature. If the partial pressures of H₂ and Br₂ at equilibrium are 0.2 atm and 0.1 atm respectively, what is the partial pressure of HBr?
Options
A 49 atm
Correct Answer
B 7.0 atm
C 2.4 × 10³ atm
D 1.1 × 10³ atm
Correct Answer

Option A is the correct answer.

Detailed Explanation

Kp = (P_HBr)²/(P_H₂ × P_Br₂). (1.2 × 10⁵) = (P_HBr)²/(0.2 × 0.1) = (P_HBr)²/0.02. P_HBr² = 1.2×10⁵ × 0.02 = 2400. P_HBr = √2400 = 49.0 atm.

Hint

Rearrange the Kp expression and solve for the unknown partial pressure.

Question Info

Course: CHM 101
Topic: CHM 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 1259 of 1872
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