Question Detail

CHM 101 CHM 101 Past Questions Objective Question
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Question

How many moles of sulfate ions (SO₄²⁻) are present in 1.50 mol of Al₂(SO₄)₃?
Options
A 1.50 mol
B 3.00 mol
C 4.50 mol
Correct Answer
D 6.00 mol
Correct Answer

Option C is the correct answer.

Detailed Explanation

Each formula unit of Al₂(SO₄)₃ contains 3 SO₄²⁻ ions. Moles SO₄²⁻ = 1.50 mol compound × 3 = 4.50 mol.

Hint

Multiply the moles of the compound by the number of sulfate ions per formula unit.

Question Info

Course: CHM 101
Topic: CHM 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 1322 of 1872
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