Question Detail

CHM 101 CHM 101 Past Questions Objective Question

Question

Calculate the number of moles in 5.00 g of Mg(NO₃)₂ (Mg=24, N=14, O=16).
Options
A 0.0337 mol
Correct Answer
B 0.100 mol
C 0.300 mol
D 0.500 mol
Correct Answer

Option A is the correct answer.

Detailed Explanation

Molar mass Mg(NO₃)₂ = 24 + 2×14 + 6×16 = 24 + 28 + 96 = 148 g/mol. Moles = 5.00/148 = 0.0338 mol ≈ 0.0337 mol.

Hint

Moles = mass / molar mass.

Question Info