Question Detail
Question
What volume of 0.500 M H₂SO₄ is required to completely react with 0.200 mol of Al according to the reaction: 2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂?
Correct Answer
Option C is the correct answer.
Detailed Explanation
The mole ratio is 2 mol Al : 3 mol H₂SO₄. Moles H₂SO₄ needed = 0.200 mol Al × (3 mol H₂SO₄ / 2 mol Al) = 0.300 mol. Volume = moles / M = 0.300 mol / 0.500 M = 0.600 L = 600 mL.
Hint
Use the balanced equation to find the mole ratio.