Question Detail
Question
A first-order reaction is 40% complete in 30 minutes. What is the rate constant for this reaction?
Correct Answer
Option A is the correct answer.
Detailed Explanation
For first order: k = (1/t) ln([A]₀/[A]). If 40% complete, [A] = 0.60[A]₀. k = (1/30) ln(1/0.60) = (1/30) × 0.5108 = 0.01703 min⁻¹ ≈ 0.0170 min⁻¹.
Hint
Use the integrated rate law: ln([A]₀/[A]) = kt.